4cos^2(x)+4sin^2(2x)=

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Solution for 4cos^2(x)+4sin^2(2x)= equation: 


Simplifying
4cos2(x) + 4sin2(2x) = 0

Multiply cos2 * x
4cos2x + 4sin2(2x) = 0

Remove parenthesis around (2x)
4cos2x + 4in2s * 2x = 0

Reorder the terms for easier multiplication:
4cos2x + 4 * 2in2s * x = 0

Multiply 4 * 2
4cos2x + 8in2s * x = 0

Multiply in2s * x
4cos2x + 8in2sx = 0

Solving
4cos2x + 8in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2sx' to each side of the equation.
4cos2x + 8in2sx + -8in2sx = 0 + -8in2sx

Combine like terms: 8in2sx + -8in2sx = 0
4cos2x + 0 = 0 + -8in2sx
4cos2x = 0 + -8in2sx
Remove the zero:
4cos2x = -8in2sx

Divide each side by '4os2x'.
c = -2in2o-1s-1

Simplifying
c = -2in2o-1s-1

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